6x^2+118x+476=0

Solution for 6x^2+118x+476=0 equation:

6x^2+118x+476=0

a = 6; b = 118; c = +476;
Δ = b2-4ac
Δ = 1182-4·6·476
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(118)-50}{2*6}=\frac{-168}{12}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(118)+50}{2*6}=\frac{-68}{12}
=-5+2/3
$